What are the solutions to the equation 4x^2+4=8x ?

The solutions to the equation 4x^2+4=8x are x=1

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4x^2+4=8x

4 x^{2} + 4 = 8 x

x = 1

Solution steps

4 x^{2} + 4 = 8 x

Move

8 x

to the left side

4 x^{2} + 4 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 8 )}{2 \cdot 4}

\frac{- ( - 8 )}{2 \cdot 4} = 1

x = 1

The solution to the quadratic equation is:

x = 1

∣ x - 3 ∣ - ∣ 2 - 3 x ∣ + ∣ 4 x - 5 ∣ + 4 \geq 0

(x^{\frac{1}{2}}) (x)

2 x^{2} - 12 x - 14 = 0

x^{3} - 7 x^{2} + 10 x \leq 0

2 x^{2} + 2 x + 20 = 0

What are the solutions to the equation 4x^2+4=8x ?
The solutions to the equation 4x^2+4=8x are x=1
Find the zeros of 4x^2+4=8x
The zeros of 4x^2+4=8x are x=1