What is (\partial)/(\partial x)(x*e^x+ln(x)y) ?

The answer to (\partial)/(\partial x)(x*e^x+ln(x)y) is e^x+e^xx+y/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x*e^x+ln(x)y)

\frac{\partial}{\partial x} (x \cdot e^{x} + ln (x) y)

e^{x} + e^{x} x + \frac{y}{x}

Solution steps

\frac{\partial}{\partial x} (x e^{x} + ln (x) y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x e^{x}) + \frac{\partial}{\partial x} (ln (x) y)

\frac{\partial}{\partial x} (x e^{x}) = e^{x} + e^{x} x

\frac{\partial}{\partial x} (ln (x) y) = \frac{y}{x}

= e^{x} + e^{x} x + \frac{y}{x}

\int - 7 ln (x^{2} - 1) d x

n = 2 \sum \infty \frac{1}{n ( n - 1 )}

\frac{d y}{d x}, 4 y^{2} - 5 y + 8 = 2 x^{2} - 3 x

\int 2 x (1 + x^{2})^{2} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 e^{2 x}

What is (\partial)/(\partial x)(x*e^x+ln(x)y) ?
The answer to (\partial)/(\partial x)(x*e^x+ln(x)y) is e^x+e^xx+y/x