What is the derivative of 4x^{2/3} ?

The derivative of 4x^{2/3} is 8/(3x^{1/3)}

What is the first derivative of 4x^{2/3} ?

The first derivative of 4x^{2/3} is 8/(3x^{1/3)}

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derivative of

4 x^{\frac{2}{3}}

\frac{8}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (4 x^{\frac{2}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

4 \cdot \frac{2}{3} x^{\frac{2}{3} - 1} : \frac{8}{3 x ^{\frac{1}{3}}}

= \frac{8}{3 x ^{\frac{1}{3}}}

\int 6 cos^{5} (x) sin^{4} (x) d x

x^{\frac{1}{2}}, x = 9

\frac{\partial}{\partial x} (b x e^{2 x y})

\int 4 x^{2} + 9 x^{4} d x

\frac{d}{d x} (1 0^{n x})

What is the derivative of 4x^{2/3} ?
The derivative of 4x^{2/3} is 8/(3x^{1/3)}
What is the first derivative of 4x^{2/3} ?
The first derivative of 4x^{2/3} is 8/(3x^{1/3)}