What is the tangent of y=-x^3+9x^2-6x+9,(7,65) ?

The tangent of y=-x^3+9x^2-6x+9,(7,65) is y=-27x+254

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tangent of y=-x^3+9x^2-6x+9,(7,65)

tangent of

y = - x^{3} + 9 x^{2} - 6 x + 9, (7, 65)

y = - 27 x + 254

Solution steps

Find the slope of

y = - x^{3} + 9 x^{2} - 6 x + 9 : \frac{d y}{d x} = - 3 x^{2} + 18 x - 6

Compute the slope of

y = - x^{3} + 9 x^{2} - 6 x + 9

(7, 65) : m = - 27

Find the line with slope m=

- 27

and passing through

(7, 65) : y = - 27 x + 254

y = - 27 x + 254

y^{^{'}} = \frac{4 x ^{3} + 1}{2 y - 6}

\frac{d}{d t} (\frac{t sin ( t )}{1 + t})

\int 0.1 x^{2} d x

\int \frac{6}{x ^{2} - x - 2} d x

y^{^{'}} (1 - x y^{1985}) = y^{1986}

What is the tangent of y=-x^3+9x^2-6x+9,(7,65) ?
The tangent of y=-x^3+9x^2-6x+9,(7,65) is y=-27x+254