What is the solution for y^'(1-xy^{1985})=y^{1986} ?

The solution for y^'(1-xy^{1985})=y^{1986} is y=-1/(\sqrt[1985]{1985(x+c_{1))}}

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y^'(1-xy^{1985})=y^{1986}

y^{^{'}} (1 - x y^{1985}) = y^{1986}

Solution steps

y^{'} (x) = y^{1986}

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y^{^{'}} + y cos (x) = 0

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\int_{1}^{2} \frac{x ^{2} + 8}{3 x - x ^{2}} d x

What is the solution for y^'(1-xy^{1985})=y^{1986} ?
The solution for y^'(1-xy^{1985})=y^{1986} is y=-1/(\sqrt[1985]{1985(x+c_{1))}}