What is the derivative of e^{3e^x} ?

The derivative of e^{3e^x} is 3e^{3e^x+x}

What is the first derivative of e^{3e^x} ?

The first derivative of e^{3e^x} is 3e^{3e^x+x}

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derivative of

e^{3 e^{x}}

3 e^{3 e^{x} + x}

Solution steps

\frac{d}{d x} (e^{3 e^{x}})

Apply the chain rule:

e^{3 e^{x}} \frac{d}{d x} (3 e^{x})

= e^{3 e^{x}} \frac{d}{d x} (3 e^{x})

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= e^{3 e^{x}} \cdot 3 e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{3 e^{x}} e^{x} = e^{3 e^{x} + x}

= 3 e^{3 e^{x} + x}

f (x) = 2 x^{2}, at x = - 1

\int_{2}^{6} (\frac{1}{x - 2}) d x

x \to 1 lim (ln ∣ ln (x) ∣)

\frac{d y}{d t} = 8 y

What is the derivative of e^{3e^x} ?
The derivative of e^{3e^x} is 3e^{3e^x+x}
What is the first derivative of e^{3e^x} ?
The first derivative of e^{3e^x} is 3e^{3e^x+x}