What is the limit as x approaches 1 of ln|ln(x)| ?

The limit as x approaches 1 of ln|ln(x)| is -infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of ln|ln(x)|

x \to 1 lim (ln ∣ ln (x) ∣)

- \infty

Solution steps

x \to 1 lim (ln ∣ ln (x) ∣)

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 1 - lim (ln ∣ ln (x) ∣) = - \infty

x \to 1 + lim (ln ∣ ln (x) ∣) = - \infty

= - \infty

\frac{d y}{d t} = 8 y

\frac{d y}{d x} = x^{3} + 2 x + π

\int_{- 1}^{2} (- x^{2} + x + 2) d x

\frac{d}{d x} (tan (x^{3}))

\frac{sin ^{2} ( x )}{cos ^{2} ( x )}

What is the limit as x approaches 1 of ln|ln(x)| ?
The limit as x approaches 1 of ln|ln(x)| is -infinity