What is the integral from-1 to 1 of sqrt(x+2) ?

The integral from-1 to 1 of sqrt(x+2) is 2sqrt(3)-2/3

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integral from-1 to 1 of sqrt(x+2)

\int_{- 1}^{1} x + 2 d x

23 - \frac{2}{3}

Decimal Notation

2.79743 \dots

Solution steps

\int_{- 1}^{1} x + 2 d x

Apply u-substitution

: \int_{1}^{3} u d u

= \int_{1}^{3} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{3}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{3}

Compute the boundaries:

23 - \frac{2}{3}

= 23 - \frac{2}{3}

x \to 2 lim (\frac{2 - x}{2 x ^{2} - 4})

y = 9 x^{2}, y = x^{2} + 6

\int cos^{7} (y) d y

\frac{d}{d x} (- 5 cot (x))

What is the integral from-1 to 1 of sqrt(x+2) ?
The integral from-1 to 1 of sqrt(x+2) is 2sqrt(3)-2/3