What is the limit as n approaches infinity of 1/(4n) ?

The limit as n approaches infinity of 1/(4n) is 0

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limit as n approaches infinity of 1/(4n)

n \to \infty lim (\frac{1}{4 n})

0

Solution steps

n \to \infty lim (\frac{1}{4 n})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{4} \cdot n \to \infty lim (\frac{1}{n})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{1}{4} \cdot \frac{lim _{n \to \infty} ( 1 )}{lim _{n \to \infty} ( n )}

n \to \infty lim (1) = 1

n \to \infty lim (n) = \infty

= \frac{1}{4} \cdot \frac{1}{\infty}

Simplify

\frac{1}{4} \cdot \frac{1}{\infty} : 0

= 0

\int e^{\frac{- x}{4}} d x

x \to \frac{5 π}{6} lim (cos (x))

\frac{d}{d y} (\frac{x}{y ^{2}})

n = 1 \sum \infty \frac{5}{n ( n + 6 )}

2 x^{2} + 3 x y + 1 y^{3} = - 10, (- 3, - 4)

What is the limit as n approaches infinity of 1/(4n) ?
The limit as n approaches infinity of 1/(4n) is 0