What is the derivative of sqrt(2t+1) ?

The derivative of sqrt(2t+1) is 1/(sqrt(2t+1))

What is the first derivative of sqrt(2t+1) ?

The first derivative of sqrt(2t+1) is 1/(sqrt(2t+1))

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derivative of

2 t + 1

\frac{1}{2 t + 1}

Solution steps

\frac{d}{d t} (2 t + 1)

Apply the chain rule:

\frac{1}{2 2 t + 1} \frac{d}{d t} (2 t + 1)

= \frac{1}{2 2 t + 1} \frac{d}{d t} (2 t + 1)

\frac{d}{d t} (2 t + 1) = 2

= \frac{1}{2 2 t + 1} \cdot 2

Simplify

\frac{1}{2 2 t + 1} \cdot 2 : \frac{1}{2 t + 1}

= \frac{1}{2 t + 1}

x \to \infty lim (x^{2} - 25)

\frac{d y}{d x} + 8 y = 6

2 - t

(2 x + 5)^{3} (x^{5} + 3)^{6}

\int \frac{16 x}{1 - x ^{4}} d x

What is the derivative of sqrt(2t+1) ?
The derivative of sqrt(2t+1) is 1/(sqrt(2t+1))
What is the first derivative of sqrt(2t+1) ?
The first derivative of sqrt(2t+1) is 1/(sqrt(2t+1))