What is (\partial)/(\partial x)(2x^2+y^3) ?

The answer to (\partial)/(\partial x)(2x^2+y^3) is 4x

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(\partial)/(\partial x)(2x^2+y^3)

\frac{\partial}{\partial x} (2 x^{2} + y^{3})

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (y^{3})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y^{3}) = 0

= 4 x + 0

Simplify

= 4 x

f (x) = \frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

\frac{500}{12 + 5 e ^{- 0.5 t}}

\frac{d y}{d x}, x = y^{3} - 8 y^{2} + 5, (- 2, 1)

\frac{1}{s ^{2} - 2 s - 3}

x \to 0 + lim (\frac{x - [ x ]}{[ x ] - 2 x})

What is (\partial)/(\partial x)(2x^2+y^3) ?
The answer to (\partial)/(\partial x)(2x^2+y^3) is 4x