What is the sum from n=1 to infinity of (cos(npi))/(n^2) ?

The sum from n=1 to infinity of (cos(npi))/(n^2) is converges

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sum from n=1 to infinity of (cos(npi))/(n^2)

n = 1 \sum \infty \frac{cos ( nπ )}{n ^{2}}

converges

Solution steps

n = 1 \sum \infty \frac{cos ( nπ )}{n ^{2}}

Apply Alternating Series Test:

converges

= converges

x \to 2 lim (\frac{x + 47 - 7}{5 x - 10})

\frac{\partial}{\partial x} (y^{5} sin (6 x))

\int_{0}^{1} \int_{0}^{s^{5}} cos (s^{6}) d t d s

y^{^{'}} = - t y

y^{^{'}} = \frac{( x + 2 y )}{x}

What is the sum from n=1 to infinity of (cos(npi))/(n^2) ?
The sum from n=1 to infinity of (cos(npi))/(n^2) is converges