What is the derivative of (6+x)/(1-6x) ?

The derivative of (6+x)/(1-6x) is (37)/((1-6x)^2)

What is the first derivative of (6+x)/(1-6x) ?

The first derivative of (6+x)/(1-6x) is (37)/((1-6x)^2)

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derivative of

\frac{6 + x}{1 - 6 x}

\frac{37}{( 1 - 6 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6 + x}{1 - 6 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 6 + x ) ( 1 - 6 x ) - \frac{d}{d x} ( 1 - 6 x ) ( 6 + x )}{( 1 - 6 x ) ^{2}}

\frac{d}{d x} (6 + x) = 1

\frac{d}{d x} (1 - 6 x) = - 6

= \frac{1 \cdot ( 1 - 6 x ) - ( - 6 ) ( 6 + x )}{( 1 - 6 x ) ^{2}}

Simplify

\frac{1 \cdot ( 1 - 6 x ) - ( - 6 ) ( 6 + x )}{( 1 - 6 x ) ^{2}} : \frac{37}{( 1 - 6 x ) ^{2}}

= \frac{37}{( 1 - 6 x ) ^{2}}

\frac{6}{s ^{2}}

\frac{d x}{d t} = 3 x^{2} + 2 x

\frac{d}{d x} (\frac{arcsin ( x )}{1 - x ^{2}})

x \to 8 - lim (\frac{64 - x ^{2}}{x - 8})

What is the derivative of (6+x)/(1-6x) ?
The derivative of (6+x)/(1-6x) is (37)/((1-6x)^2)
What is the first derivative of (6+x)/(1-6x) ?
The first derivative of (6+x)/(1-6x) is (37)/((1-6x)^2)