What is the derivative of x+6x^{2/3} ?

The derivative of x+6x^{2/3} is 1+4/(x^{1/3)}

What is the first derivative of x+6x^{2/3} ?

The first derivative of x+6x^{2/3} is 1+4/(x^{1/3)}

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\frac{d}{d x} (x + 6 x^{\frac{2}{3}})

1 + \frac{4}{x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (x + 6 x^{\frac{2}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (6 x^{\frac{2}{3}})

\frac{d x}{d x} = 1

\frac{d}{d x} (6 x^{\frac{2}{3}}) = \frac{4}{x ^{\frac{1}{3}}}

= 1 + \frac{4}{x ^{\frac{1}{3}}}

x y^{^{'}} = x y + 2 y

\frac{d ^{2}}{d x ^{2}} (x + 2)

\int \frac{x ^{2} + 1}{x} d x

y = - \frac{1}{4} x^{2}, (- 2, - 1)

(1 + 2 x)^{2}

What is the derivative of x+6x^{2/3} ?
The derivative of x+6x^{2/3} is 1+4/(x^{1/3)}
What is the first derivative of x+6x^{2/3} ?
The first derivative of x+6x^{2/3} is 1+4/(x^{1/3)}