What is the derivative of ln(4x-1) ?

The derivative of ln(4x-1) is 4/(4x-1)

What is the first derivative of ln(4x-1) ?

The first derivative of ln(4x-1) is 4/(4x-1)

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\frac{d}{d x} (ln (4 x - 1))

\frac{4}{4 x - 1}

Solution steps

\frac{d}{d x} (ln (4 x - 1))

Apply the chain rule:

\frac{1}{4 x - 1} \frac{d}{d x} (4 x - 1)

= \frac{1}{4 x - 1} \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= \frac{1}{4 x - 1} \cdot 4

Simplify

\frac{1}{4 x - 1} \cdot 4 : \frac{4}{4 x - 1}

= \frac{4}{4 x - 1}

\int_{4}^{5} \frac{1}{5 x - 1} d x

x y^{^{'}} + 3 y = \frac{4 e ^{2 x}}{x ^{2}}

x \to 1 lim (\frac{2 x}{x - 1})

f (x) = 9 x^{5} (x^{3} - 2 x)

y^{^{''}} - 2 y^{^{'}} - 63 y = 0

What is the derivative of ln(4x-1) ?
The derivative of ln(4x-1) is 4/(4x-1)
What is the first derivative of ln(4x-1) ?
The first derivative of ln(4x-1) is 4/(4x-1)