What is the derivative of f(t)=2t^3-3t^2-4t ?

The derivative of f(t)=2t^3-3t^2-4t is 6t^2-6t-4

What is the first derivative of f(t)=2t^3-3t^2-4t ?

The first derivative of f(t)=2t^3-3t^2-4t is 6t^2-6t-4

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derivative of

f (t) = 2 t^{3} - 3 t^{2} - 4 t

6 t^{2} - 6 t - 4

Solution steps

\frac{d}{d t} (2 t^{3} - 3 t^{2} - 4 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t^{3}) - \frac{d}{d t} (3 t^{2}) - \frac{d}{d t} (4 t)

\frac{d}{d t} (2 t^{3}) = 6 t^{2}

\frac{d}{d t} (3 t^{2}) = 6 t

\frac{d}{d t} (4 t) = 4

= 6 t^{2} - 6 t - 4

\frac{\partial}{\partial x} (\frac{4 π ^{2} x}{y ^{2}})

9 x e^{x} csc (x)

\frac{1}{x}, 1, 2

\int \frac{( x ^{2} + 1 )}{( x - 3 ) ( x - 2 ) ^{2}} d x

\frac{d y}{d x}, x y^{3} + 10 y^{11} = 9

What is the derivative of f(t)=2t^3-3t^2-4t ?
The derivative of f(t)=2t^3-3t^2-4t is 6t^2-6t-4
What is the first derivative of f(t)=2t^3-3t^2-4t ?
The first derivative of f(t)=2t^3-3t^2-4t is 6t^2-6t-4