What is the derivative of y=ln(x-3) ?

The derivative of y=ln(x-3) is 1/(x-3)

What is the first derivative of y=ln(x-3) ?

The first derivative of y=ln(x-3) is 1/(x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = ln (x - 3)

\frac{1}{x - 3}

Solution steps

\frac{d}{d x} (ln (x - 3))

Apply the chain rule:

\frac{1}{x - 3} \frac{d}{d x} (x - 3)

= \frac{1}{x - 3} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= \frac{1}{x - 3} \cdot 1

Simplify

= \frac{1}{x - 3}

\int 7 cos (x) cos^{5} (sin (x)) d x

\frac{d}{d x} (9 x + 8)

\int \frac{tan ( x )}{sec ( x ) + 4 cos ( x )} d x

\int 12 x + 5 d x

\frac{\partial}{\partial x} (cos (4 y^{2} - 2 x))

What is the derivative of y=ln(x-3) ?
The derivative of y=ln(x-3) is 1/(x-3)
What is the first derivative of y=ln(x-3) ?
The first derivative of y=ln(x-3) is 1/(x-3)