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Popular >

y^'+2/x y=-2xy^2

Solution

y^{^{'}} + \frac{2}{x} y = - 2 x y^{2}

Solution

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

Solution steps

y^{'} (x) + \frac{2}{x} y = - 2 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

Popular Examples

tangent of 3x^2+7x-4 tangent of

3 x^{2} + 7 x - 4

derivative of sqrt(1-289x^2)arccos(17x)derivative of

1 - 289 x^{2} arccos (17 x)

limit as h approaches 0 of (((1/(1-(x+h)))-(1/(1-x))))/h

h \to 0 lim \frac{( ( \frac{1}{1 - ( x + h )} ) - ( \frac{1}{1 - x} ) )}{h}

derivative of 1/((x+y))

\frac{d}{d x} (\frac{1}{( x + y )})

limit as x approaches+0+of (1+x)^{(1/x)}

x \to + 0 + lim ((1 + x)^{(\frac{1}{x})})

Frequently Asked Questions (FAQ)

What is the solution for y^'+2/x y=-2xy^2 ?
The solution for y^'+2/x y=-2xy^2 is y= 1/(x^2(2ln(x)+c_{1))}