What is the solution for y^'=(x-2)/(y-2) ?

The solution for y^'=(x-2)/(y-2) is y=2+sqrt(x^2-4x+c_{1)+4},y=2-sqrt(x^2-4x+c_{1)+4}

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y^'=(x-2)/(y-2)

y^{^{'}} = \frac{x - 2}{y - 2}

y = 2 + x^{2} - 4 x + c_{1} + 4, y = 2 - x^{2} - 4 x + c_{1} + 4

Solution steps

y^{'} (x) = \frac{x - 2}{y - 2}

Solve separable ODE:

y = 2 + x^{2} - 4 x + c_{1} + 4, y = 2 - x^{2} - 4 x + c_{1} + 4

y = 2 + x^{2} - 4 x + c_{1} + 4, y = 2 - x^{2} - 4 x + c_{1} + 4

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} + 5 z^{2})

y = (\frac{( x + 2 )}{( x - 2 ) ^{2}}), at x = 3

\frac{d}{d x} (\frac{x ^{2} - 3}{e ^{x}})

f (x) = (x^{2} + 5)^{9}

\int t^{3} e^{t^{2}} d t

What is the solution for y^'=(x-2)/(y-2) ?
The solution for y^'=(x-2)/(y-2) is y=2+sqrt(x^2-4x+c_{1)+4},y=2-sqrt(x^2-4x+c_{1)+4}