What is the derivative of-(sin(x))/(cos(x)) ?

The derivative of-(sin(x))/(cos(x)) is -sec^2(x)

What is the first derivative of-(sin(x))/(cos(x)) ?

The first derivative of-(sin(x))/(cos(x)) is -sec^2(x)

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derivative of

- \frac{sin ( x )}{cos ( x )}

- sec^{2} (x)

Solution steps

\frac{d}{d x} (- \frac{sin ( x )}{cos ( x )})

Simplify

- \frac{sin ( x )}{cos ( x )} : - tan (x)

= \frac{d}{d x} (- tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (tan (x))

Apply the common derivative:

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= - sec^{2} (x)

x^{^{'}} - 10 x = 0

y^{^{''}} - 12 y^{^{'}} + 36 y = 30 x + 2

\int 12 y d y

f (x) = \frac{1}{4 x ^{2} + 5 x}

\frac{925 + 20 x - 0.079 x ^{2}}{484}

What is the derivative of-(sin(x))/(cos(x)) ?
The derivative of-(sin(x))/(cos(x)) is -sec^2(x)
What is the first derivative of-(sin(x))/(cos(x)) ?
The first derivative of-(sin(x))/(cos(x)) is -sec^2(x)