What is the sum from n=0 to infinity of (-5/6)^n ?

The sum from n=0 to infinity of (-5/6)^n is 6/11

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sum from n=0 to infinity of (-5/6)^n

n = 0 \sum \infty (- \frac{5}{6})^{n}

\frac{6}{11}

Solution steps

n = 0 \sum \infty (- \frac{5}{6})^{n}

Apply Series Geometric Test:

\frac{6}{11}

= \frac{6}{11}

\int cos^{2} (θ) + sin^{2} (θ) d θ

\frac{\partial ^{2}}{\partial x \partial y} (\frac{x y}{x - y})

x \to + 0 lim (x^{4} cos (\frac{π}{x}))

f (x) = \frac{e ^{x}}{2 + 4 x}

f (x) = - 2 sin (2 x)

What is the sum from n=0 to infinity of (-5/6)^n ?
The sum from n=0 to infinity of (-5/6)^n is 6/11