What is the f(x)=(-4x^2+3x-7)/(2x^2-10x-3) ?

The f(x)=(-4x^2+3x-7)/(2x^2-10x-3) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=(-4x^2+3x-7)/(2x^2-10x-3)

f (x) = \frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3}

Domain : x < \frac{5 - 31}{2} or \frac{5 - 31}{2} < x < \frac{5 + 31}{2} or x > \frac{5 + 31}{2}

Range : f (x) \leq - \frac{41}{31 2} - \frac{13}{62} or f (x) \geq \frac{41}{31 2} - \frac{13}{62}

Y Intercepts : (0, \frac{7}{3})

Asymptotes : Vertical x = \frac{5 - 31}{2}, x = \frac{5 + 31}{2}, Horizontal y = - 2

Extreme Points : Maximum (- \frac{26 + 41 2}{34}, - \frac{13 + 41 2}{62}), Minimum (\frac{- 26 + 41 2}{34}, \frac{41 2 - 13}{62})

Interval Notation

Domain : (- \infty, \frac{5 - 31}{2}) \cup (\frac{5 - 31}{2}, \frac{5 + 31}{2}) \cup (\frac{5 + 31}{2}, \infty)

Range : (- \infty, - \frac{41}{31 2} - \frac{13}{62}] \cup [\frac{41}{31 2} - \frac{13}{62}, \infty)

Solution steps

Domain of

\frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3} : x < \frac{5 - 31}{2} or \frac{5 - 31}{2} < x < \frac{5 + 31}{2} or x > \frac{5 + 31}{2}

Range of

\frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3} : f (x) \leq - \frac{41}{31 2} - \frac{13}{62} or f (x) \geq \frac{41}{31 2} - \frac{13}{62}

Axis interception points of

\frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3} :

Y Intercepts

: (0, \frac{7}{3})

Asymptotes of

\frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3} :

Vertical

: x = \frac{5 - 31}{2}, x = \frac{5 + 31}{2},

Horizontal

: y = - 2

Extreme Points of

\frac{- 4 x ^{2} + 3 x - 7}{2 x ^{2} - 10 x - 3} :

Maximum

(- \frac{26 + 41 2}{34}, - \frac{13 + 41 2}{62}),

Minimum

(\frac{- 26 + 41 2}{34}, \frac{41 2 - 13}{62})

\int \frac{1}{x ( x ^{2} + 5 )} d x

\int - e^{- k t} k M d t

\frac{\partial}{\partial x} (arctan (x y) - z)

x \to 0 lim (- 3 (- 6) + 3 (- 5))

y = x^{3} - 4 x, - 2 \leq x \leq 2

What is the f(x)=(-4x^2+3x-7)/(2x^2-10x-3) ?
The f(x)=(-4x^2+3x-7)/(2x^2-10x-3) is