What is (\partial)/(\partial y)((7y)/(x^4)) ?

The answer to (\partial)/(\partial y)((7y)/(x^4)) is 7/(x^4)

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(\partial)/(\partial y)((7y)/(x^4))

\frac{\partial}{\partial y} (\frac{7 y}{x ^{4}})

\frac{7}{x ^{4}}

Solution steps

\frac{\partial}{\partial y} (\frac{7 y}{x ^{4}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{x ^{4}} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= \frac{7}{x ^{4}} \cdot 1

Simplify

= \frac{7}{x ^{4}}

x \to 1 lim (2 x - 5)

\frac{d}{d x} (\frac{1}{8} x^{2})

\int_{0}^{1} (1 - x)^{2} d x

\frac{\partial}{\partial x} (- y^{2} sin (x y^{2}))

\frac{d}{d x} ((x - 1)^{4})

What is (\partial)/(\partial y)((7y)/(x^4)) ?
The answer to (\partial)/(\partial y)((7y)/(x^4)) is 7/(x^4)