What is the derivative of 3x^3+2x+9 ?

The derivative of 3x^3+2x+9 is 9x^2+2

What is the first derivative of 3x^3+2x+9 ?

The first derivative of 3x^3+2x+9 is 9x^2+2

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\frac{d}{d x} (3 x^{3} + 2 x + 9)

9 x^{2} + 2

Solution steps

\frac{d}{d x} (3 x^{3} + 2 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (9) = 0

= 9 x^{2} + 2 + 0

Simplify

= 9 x^{2} + 2

x \to 0 + lim ((csc (x))^{x})

\frac{\partial}{\partial x} (x \cdot sin (y) \cdot sin (z))

x^{2} + 6 x + 3

\frac{d}{d x} (3 \frac{1 + x ^{3}}{1 - x ^{3}})

x \to 8 + lim (ln (x^{2} - 64))

What is the derivative of 3x^3+2x+9 ?
The derivative of 3x^3+2x+9 is 9x^2+2
What is the first derivative of 3x^3+2x+9 ?
The first derivative of 3x^3+2x+9 is 9x^2+2