What is the integral from 15 to 35 of (x^2x) ?

The integral from 15 to 35 of (x^2x) is 362500

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integral from 15 to 35 of (x^2x)

\int_{15}^{35} (x^{2} x) d x

362500

Solution steps

\int_{15}^{35} x^{2} x d x

Simplify

x^{2} x : x^{3}

= \int_{15}^{35} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{15}^{35}

= [\frac{x ^{4}}{4}]_{15}^{35}

Compute the boundaries:

362500

= 362500

\frac{\partial}{\partial y} (\frac{x}{y} - yz)

\int \frac{3 x - 1}{x ^{\frac{2}{3}}} d x

\int \frac{( x - 1 )}{x ^{3} + x ^{2} + 6 x} d x

x \to 4 - lim (4 x)

\frac{d}{d x} (\frac{1}{3 x ^{2} + 1})

What is the integral from 15 to 35 of (x^2x) ?
The integral from 15 to 35 of (x^2x) is 362500