What is the derivative of 1/(3x^2+1) ?

The derivative of 1/(3x^2+1) is -(6x)/((3x^2+1)^2)

What is the first derivative of 1/(3x^2+1) ?

The first derivative of 1/(3x^2+1) is -(6x)/((3x^2+1)^2)

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\frac{d}{d x} (\frac{1}{3 x ^{2} + 1})

- \frac{6 x}{( 3 x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{2} + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 x^{2} + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x ^{2} + 1 ) ^{2}} \frac{d}{d x} (3 x^{2} + 1)

= - \frac{1}{( 3 x ^{2} + 1 ) ^{2}} \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= - \frac{1}{( 3 x ^{2} + 1 ) ^{2}} \cdot 6 x

Simplify

- \frac{1}{( 3 x ^{2} + 1 ) ^{2}} \cdot 6 x : - \frac{6 x}{( 3 x ^{2} + 1 ) ^{2}}

= - \frac{6 x}{( 3 x ^{2} + 1 ) ^{2}}

\int x^{2} e^{4 x^{3}} d x

n = 0 \sum \infty 1^{l n (n)}

y = \frac{1}{2} e^{2 x} + e^{x} + 1

3 sin (4 x)

\frac{d}{d x} (x^{4} + cos (x) + 1)

What is the derivative of 1/(3x^2+1) ?
The derivative of 1/(3x^2+1) is -(6x)/((3x^2+1)^2)
What is the first derivative of 1/(3x^2+1) ?
The first derivative of 1/(3x^2+1) is -(6x)/((3x^2+1)^2)