What is the derivative of 3sin(4x) ?

The derivative of 3sin(4x) is 12cos(4x)

What is the first derivative of 3sin(4x) ?

The first derivative of 3sin(4x) is 12cos(4x)

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derivative of

3 sin (4 x)

12 cos (4 x)

Solution steps

\frac{d}{d x} (3 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 3 cos (4 x) \cdot 4

Simplify

= 12 cos (4 x)

\frac{d}{d x} (x^{4} + cos (x) + 1)

\int \frac{( 16 - 9 x ^{2} ) ^{\frac{3}{2}}}{x ^{6}} d x

\int \frac{16}{( x + 2 ) ^{2}} d x

y^{^{'}} = y + x y

n = 1 \sum \infty (\frac{( 3 n - 1 )}{( 3 n )})^{n^{2}}

What is the derivative of 3sin(4x) ?
The derivative of 3sin(4x) is 12cos(4x)
What is the first derivative of 3sin(4x) ?
The first derivative of 3sin(4x) is 12cos(4x)