What is the tangent of y=cos(x),\at x=(3pi)/2 ?

The tangent of y=cos(x),\at x=(3pi)/2 is y=x-(3pi)/2

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tangent of y=cos(x),\at x=(3pi)/2

tangent of

y = cos (x), at x = \frac{3 π}{2}

y = x - \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{3 π}{2}, 0)

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = \frac{3 π}{2} : m = 1

Find the line with slope m=

1

and passing through

(\frac{3 π}{2}, 0) : y = x - \frac{3 π}{2}

y = x - \frac{3 π}{2}

f (x) = \frac{5}{( 2 x - 3 ) ^{4}}

\frac{d}{d x} (sin (x) ln (5 x))

e^{19}

\frac{d y}{d x} = e^{4} x + 7 y

\int x 3 x^{2} - 6 d x

What is the tangent of y=cos(x),\at x=(3pi)/2 ?
The tangent of y=cos(x),\at x=(3pi)/2 is y=x-(3pi)/2