What is the derivative of 3(x-2^2) ?

The derivative of 3(x-2^2) is 6(x-2)

What is the first derivative of 3(x-2^2) ?

The first derivative of 3(x-2^2) is 6(x-2)

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\frac{d}{d x} (3 (x - 2)^{2})

6 (x - 2)

Solution steps

\frac{d}{d x} (3 (x - 2)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((x - 2)^{2})

Apply the chain rule:

2 (x - 2) \frac{d}{d x} (x - 2)

= 2 (x - 2) \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 3 \cdot 2 (x - 2) \cdot 1

Simplify

= 6 (x - 2)

y = 2 x - x + 1, (4, 1)

y = x e^{- x^{2}}

\int \frac{x + 3}{x - 2} d x

\frac{t ^{2}}{t - 2}

\int (6 x^{5} + 7 x) d x

What is the derivative of 3(x-2^2) ?
The derivative of 3(x-2^2) is 6(x-2)
What is the first derivative of 3(x-2^2) ?
The first derivative of 3(x-2^2) is 6(x-2)