What is the derivative of f(x)=(3x^2-18x+15)/5 ?

The derivative of f(x)=(3x^2-18x+15)/5 is 1/5 (6x-18)

What is the first derivative of f(x)=(3x^2-18x+15)/5 ?

The first derivative of f(x)=(3x^2-18x+15)/5 is 1/5 (6x-18)

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derivative of

f (x) = \frac{3 x ^{2} - 18 x + 15}{5}

\frac{1}{5} (6 x - 18)

Solution steps

\frac{d}{d x} (\frac{3 x ^{2} - 18 x + 15}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (3 x^{2} - 18 x + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{5} (\frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (18 x) + \frac{d}{d x} (15))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (15) = 0

= \frac{1}{5} (6 x - 18 + 0)

Simplify

= \frac{1}{5} (6 x - 18)

\frac{d}{d x} (\frac{3 sin ( x )}{3 + cos ( x )})

\frac{\partial}{\partial y} (2 x^{3} y + 4)

\int (x^{\frac{3}{2}} + 1)^{2} d x

f (x) = sin (sin (sin (x)))

\frac{d y}{d x}, e^{x y} + x^{2} - y^{2} = 12

What is the derivative of f(x)=(3x^2-18x+15)/5 ?
The derivative of f(x)=(3x^2-18x+15)/5 is 1/5 (6x-18)
What is the first derivative of f(x)=(3x^2-18x+15)/5 ?
The first derivative of f(x)=(3x^2-18x+15)/5 is 1/5 (6x-18)