What is the sum from n=0 to infinity of (1/17)^n ?

The sum from n=0 to infinity of (1/17)^n is 17/16

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sum from n=0 to infinity of (1/17)^n

n = 0 \sum \infty (\frac{1}{17})^{n}

\frac{17}{16}

Solution steps

n = 0 \sum \infty (\frac{1}{17})^{n}

Apply Series Geometric Test:

\frac{17}{16}

= \frac{17}{16}

f (x) = \frac{4 x + 5}{x - 1}, at x = 2

x \to 0 lim (\frac{sin ( 5 x )}{6 x})

f (x) = 3 sec (5 x)

\frac{\partial}{\partial x} (\frac{17}{2} x^{4} y)

f (x) = x^{2} + x, at x = 1

What is the sum from n=0 to infinity of (1/17)^n ?
The sum from n=0 to infinity of (1/17)^n is 17/16