What is the solution for y^'= x/y+y/x ?

The solution for y^'= x/y+y/x is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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y^'= x/y+y/x

y^{^{'}} = \frac{x}{y} + \frac{y}{x}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{x}{y} + \frac{y}{x}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = 6 + 2 x, y = \frac{12 + x}{2}

\frac{d}{d x} (2 (x^{2} - 1))

x \to \infty lim (\frac{x}{1})

\frac{\partial}{\partial x} (ln (x^{5} + y^{4}))

What is the solution for y^'= x/y+y/x ?
The solution for y^'= x/y+y/x is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}