What is area y=6+2sqrt(x),y=(12+x)/2 ?

The answer to area y=6+2sqrt(x),y=(12+x)/2 is 64/3

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area y=6+2sqrt(x),y=(12+x)/2

area

y = 6 + 2 x, y = \frac{12 + x}{2}

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{16} 6 + 2 x - \frac{12 + x}{2} d x

Solve

\int_{0}^{16} 6 + 2 x - \frac{12 + x}{2} d x : \frac{64}{3}

The area is:

= \frac{64}{3}

\frac{d}{d x} (2 (x^{2} - 1))

x \to \infty lim (\frac{x}{1})

\frac{\partial}{\partial x} (ln (x^{5} + y^{4}))

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} - 16 y = 1

What is area y=6+2sqrt(x),y=(12+x)/2 ?
The answer to area y=6+2sqrt(x),y=(12+x)/2 is 64/3