What is the solution for (d^2y)/(dx^2)+6(dy)/(dx)-16y=1 ?

The solution for (d^2y)/(dx^2)+6(dy)/(dx)-16y=1 is y=c_{1}e^{2x}+c_{2}e^{-8x}-1/16

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(d^2y)/(dx^2)+6(dy)/(dx)-16y=1

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} - 16 y = 1

y = c_{1} e^{2 x} + c_{2} e^{- 8 x} - \frac{1}{16}

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} - 16 y = 1

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 8 x} - \frac{1}{16}

y = c_{1} e^{2 x} + c_{2} e^{- 8 x} - \frac{1}{16}

\frac{\partial}{\partial x} (8 x y + 5 yz + x y - 56)

x \to - 4 + lim (\frac{x}{x + 4})

\int x e^{x^{2} + 3} d x

\int 3 sec^{2} (3 x) d x

x \to 1 lim (\frac{x}{ln ( x )})

What is the solution for (d^2y)/(dx^2)+6(dy)/(dx)-16y=1 ?
The solution for (d^2y)/(dx^2)+6(dy)/(dx)-16y=1 is y=c_{1}e^{2x}+c_{2}e^{-8x}-1/16