What is (\partial)/(\partial x)(8xy+5yz+xy-56) ?

The answer to (\partial)/(\partial x)(8xy+5yz+xy-56) is 9y

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(\partial)/(\partial x)(8xy+5yz+xy-56)

\frac{\partial}{\partial x} (8 x y + 5 yz + x y - 56)

9 y

Solution steps

\frac{\partial}{\partial x} (8 x y + 5 yz + x y - 56)

Simplify

8 x y + 5 yz + x y - 56 : 9 x y + 5 yz - 56

= \frac{\partial}{\partial x} (9 x y + 5 yz - 56)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x y) + \frac{\partial}{\partial x} (5 yz) - \frac{\partial}{\partial x} (56)

\frac{\partial}{\partial x} (9 x y) = 9 y

\frac{\partial}{\partial x} (5 yz) = 0

\frac{\partial}{\partial x} (56) = 0

= 9 y + 0 - 0

Simplify

= 9 y

x \to - 4 + lim (\frac{x}{x + 4})

\int x e^{x^{2} + 3} d x

\int 3 sec^{2} (3 x) d x

x \to 1 lim (\frac{x}{ln ( x )})

\frac{d}{d x} ((x^{2})^{3})

What is (\partial)/(\partial x)(8xy+5yz+xy-56) ?
The answer to (\partial)/(\partial x)(8xy+5yz+xy-56) is 9y