What is inverse oflaplace-2/(s+1/3) ?

The answer to inverse oflaplace-2/(s+1/3) is -2e^{-t/3}

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inverse oflaplace-2/(s+1/3)

inverse laplace

- \frac{2}{s + \frac{1}{3}}

- 2 e^{- \frac{t}{3}}

Solution steps

L^{- 1} {- \frac{2}{s + \frac{1}{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {\frac{2}{s + \frac{1}{3}}}

L^{- 1} {\frac{2}{s + \frac{1}{3}}} : 2 e^{- \frac{t}{3}}

= - 2 e^{- \frac{t}{3}}

\frac{\partial}{\partial x} (sin (π (2 x - 3 y)))

x \to 0 + lim ((2 x^{2} + x)^{x})

x \to 3 lim (\frac{( x + 2 )}{x + 3})

e^{2 x}, x = 0

x \to 2 lim (- 4 x^{2} - 3 x + 6)

What is inverse oflaplace-2/(s+1/3) ?
The answer to inverse oflaplace-2/(s+1/3) is -2e^{-t/3}