What is the tangent of 4-3/(x^2),\at x=4 ?

The tangent of 4-3/(x^2),\at x=4 is y= 3/32 x+55/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 4-3/(x^2),\at x=4

tangent of

4 - \frac{3}{x ^{2}}, at x = 4

y = \frac{3}{32} x + \frac{55}{16}

Solution steps

Find the tangent point:

(4, \frac{61}{16})

Find the slope of

y = 4 - \frac{3}{x ^{2}} : \frac{d y}{d x} = \frac{6}{x ^{3}}

Compute the slope of

y = 4 - \frac{3}{x ^{2}}

x = 4 : m = \frac{3}{32}

Find the line with slope m=

\frac{3}{32}

and passing through

(4, \frac{61}{16}) : y = \frac{3}{32} x + \frac{55}{16}

y = \frac{3}{32} x + \frac{55}{16}

f (x) = \frac{2 x - 1}{x + 9}, at x = 1

f (x) = \frac{( 4 - 2 x ) ^{5}}{x ^{3} + 12}

x \to \infty lim (x^{2} - 3)

y^{^{''}} - 2 y + 6 = 0

What is the tangent of 4-3/(x^2),\at x=4 ?
The tangent of 4-3/(x^2),\at x=4 is y= 3/32 x+55/16