What is the derivative of e^x+e^x ?

The derivative of e^x+e^x is 2e^x

What is the first derivative of e^x+e^x ?

The first derivative of e^x+e^x is 2e^x

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\frac{d}{d x} (e^{x} + e^{x})

2 e^{x}

Solution steps

\frac{d}{d x} (e^{x} + e^{x})

Simplify

e^{x} + e^{x} : 2 e^{x}

= \frac{d}{d x} (2 e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x})

Apply the common derivative:

\frac{d}{d x} (e^{x}) = e^{x}

= 2 e^{x}

\frac{\partial}{\partial y} (sin (x) cos (x))

9 e^{- x}

f (x) = arctan (- 6 x)

x \to 2 lim (8 - 2 x)

x \to - 4 + lim (\frac{1}{x ^{2} - 16})

What is the derivative of e^x+e^x ?
The derivative of e^x+e^x is 2e^x
What is the first derivative of e^x+e^x ?
The first derivative of e^x+e^x is 2e^x