What is the derivative of (x^2-1)^3 ?

The derivative of (x^2-1)^3 is 6x(x^2-1)^2

What is the first derivative of (x^2-1)^3 ?

The first derivative of (x^2-1)^3 is 6x(x^2-1)^2

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derivative of

(x^{2} - 1)^{3}

6 x (x^{2} - 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} - 1)^{3})

Apply the chain rule:

3 (x^{2} - 1)^{2} \frac{d}{d x} (x^{2} - 1)

= 3 (x^{2} - 1)^{2} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 3 (x^{2} - 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} - 1)^{2}

\frac{s}{( s ^{2} - 1 ) ^{2}}

\frac{d}{d x} (- ln^{4} (2 sin^{2} (x)^{3} - 1))

x y^{^{'}} = \frac{1}{x y}

\int (\frac{x ^{3}}{1 + x ^{4}}) d x

\frac{\partial}{\partial x} (e^{4 x y} ln (7 y))

What is the derivative of (x^2-1)^3 ?
The derivative of (x^2-1)^3 is 6x(x^2-1)^2
What is the first derivative of (x^2-1)^3 ?
The first derivative of (x^2-1)^3 is 6x(x^2-1)^2