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Popular >

2xy^'+y=8x^3

Solution

2 x y^{^{'}} + y = 8 x^{3}

Solution

y = \frac{8 x ^{3}}{7} + \frac{c _{1}}{x}

Solution steps

2 x y^{'} (x) + y = 8 x^{3}

Solve linear ODE:

y = \frac{8 x ^{3}}{7} + \frac{c _{1}}{x}

y = \frac{8 x ^{3}}{7} + \frac{c _{1}}{x}

Popular Examples

limit as (x,y) approaches (0,1) of x^3y

(x, y) \to (0, 1) lim (x^{3} y)

limit as x approaches 0 of 5x+2

x \to 0 lim (5 x + 2)

limit as x approaches-2 of 2^x

x \to - 2 lim (2^{x})

derivative of ln^2(sqrt(x^2+5x+8))

\frac{d}{d x} (ln^{2} (x^{2} + 5 x + 8))

limit as x approaches 0+of e^{(-1/x)}

x \to 0 + lim (e^{(- \frac{1}{x})})

Frequently Asked Questions (FAQ)

What is the solution for 2xy^'+y=8x^3 ?
The solution for 2xy^'+y=8x^3 is y=(8x^3)/7+(c_{1})/(sqrt(x))