What is the derivative of (x+1^2) ?

The derivative of (x+1^2) is 2(x+1)

What is the first derivative of (x+1^2) ?

The first derivative of (x+1^2) is 2(x+1)

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\frac{d}{d x} ((x + 1)^{2})

2 (x + 1)

Solution steps

\frac{d}{d x} ((x + 1)^{2})

Apply the chain rule:

2 (x + 1) \frac{d}{d x} (x + 1)

= 2 (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 (x + 1) \cdot 1

Simplify

= 2 (x + 1)

x \to 1 - lim (\frac{x + 1}{x ^{4} - 1})

x^{2} y^{^{''}} - 2 x y^{^{'}} - 4 y = 0, y (1) = 0, y^{^{'}} (1) = - 5

\frac{d}{d x} (x^{4} - \frac{x ^{8}}{6} - x^{2} sin (x^{2}))

\int (5 x + 4)^{3} d x

\frac{\partial}{\partial x} (sin^{2} (t))

What is the derivative of (x+1^2) ?
The derivative of (x+1^2) is 2(x+1)
What is the first derivative of (x+1^2) ?
The first derivative of (x+1^2) is 2(x+1)