What is the derivative of 2/(r^3) ?

The derivative of 2/(r^3) is -6/(r^4)

What is the first derivative of 2/(r^3) ?

The first derivative of 2/(r^3) is -6/(r^4)

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derivative of

\frac{2}{r ^{3}}

- \frac{6}{r ^{4}}

Solution steps

\frac{d}{d r} (\frac{2}{r ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d r} (\frac{1}{r ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d r} (r^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 r^{- 3 - 1})

Simplify

2 (- 3 r^{- 3 - 1}) : - \frac{6}{r ^{4}}

= - \frac{6}{r ^{4}}

x \to 0 lim (\frac{1}{ln ( x )})

\frac{2}{s ( s ^{2} + 4 )}

f (x) = - 2 cos (2 x)

\int_{0}^{\frac{π}{2}} 9 sin^{2} (3 x) d x

n = 1 \sum \infty n e^{- 2 n}

What is the derivative of 2/(r^3) ?
The derivative of 2/(r^3) is -6/(r^4)
What is the first derivative of 2/(r^3) ?
The first derivative of 2/(r^3) is -6/(r^4)