What is the sum from n=1 to infinity of ne^{-2n} ?

The sum from n=1 to infinity of ne^{-2n} is converges

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sum from n=1 to infinity of ne^{-2n}

n = 1 \sum \infty n e^{- 2 n}

converges

Solution steps

n = 1 \sum \infty n e^{- 2 n}

Apply Series Ratio Test:

converges

= converges

(x + y) d x - (x + y + 3) d y = 0

y = x^{3} - 3 x + 2, (4, 54)

\frac{s ^{2} + 12}{s ^{4} - 16}

\frac{d}{d x} (\frac{x ^{2}}{2 - x})

What is the sum from n=1 to infinity of ne^{-2n} ?
The sum from n=1 to infinity of ne^{-2n} is converges