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Popular >

(x^2+5)y^'=xy

Solution

(x^{2} + 5) y^{^{'}} = x y

Solution

y = c_{1} x^{2} + 5

Solution steps

(x^{2} + 5) y^{'} (x) = x y

Solve separable ODE:

y = c_{1} x^{2} + 5

y = c_{1} x^{2} + 5

Popular Examples

area y=3x^2,(0,1)area

y = 3 x^{2}, (0, 1)

derivative of (x^3+9e^x)

\frac{d}{d x} ((x^{3} + 9) e^{x})

integral from 2 to 7 of 4/(8x-11)

\int_{2}^{7} \frac{4}{8 x - 11} d x

derivative of (6x^2+2x+6)/(sqrt(x))derivative of

\frac{6 x ^{2} + 2 x + 6}{x}

tangent of y=tan(x),\at x= pi/4 tangent of

y = tan (x), at x = \frac{π}{4}

Frequently Asked Questions (FAQ)

What is the solution for (x^2+5)y^'=xy ?
The solution for (x^2+5)y^'=xy is y=c_{1}sqrt(x^2+5)