What is the derivative of 2x(7x^2-2^4) ?

The derivative of 2x(7x^2-2^4) is 2((7x^2-2)^4+56x^2(7x^2-2)^3)

What is the first derivative of 2x(7x^2-2^4) ?

The first derivative of 2x(7x^2-2^4) is 2((7x^2-2)^4+56x^2(7x^2-2)^3)

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\frac{d}{d x} (2 x (7 x^{2} - 2)^{4})

2 ((7 x^{2} - 2)^{4} + 56 x^{2} (7 x^{2} - 2)^{3})

Solution steps

\frac{d}{d x} (2 x (7 x^{2} - 2)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x (7 x^{2} - 2)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (7 x^{2} - 2)^{4}

= 2 (\frac{d x}{d x} (7 x^{2} - 2)^{4} + \frac{d}{d x} ((7 x^{2} - 2)^{4}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((7 x^{2} - 2)^{4}) = 56 x (7 x^{2} - 2)^{3}

= 2 (1 \cdot (7 x^{2} - 2)^{4} + 56 x (7 x^{2} - 2)^{3} x)

Simplify

2 (1 \cdot (7 x^{2} - 2)^{4} + 56 x (7 x^{2} - 2)^{3} x) : 2 ((7 x^{2} - 2)^{4} + 56 x^{2} (7 x^{2} - 2)^{3})

= 2 ((7 x^{2} - 2)^{4} + 56 x^{2} (7 x^{2} - 2)^{3})

\int_{0}^{l n (5)} e^{x} (3 - 4 e^{x}) d x

y = e^{2}, x = 0, x = 3

\frac{d}{d x} (x e^{r (x) x})

\frac{d}{d x} (lo g_{5} (arccos (x^{3} - 2)))

\frac{\partial}{\partial x} (- 2 e^{y} sin (- x) + 3 y - 4 x y)

What is the derivative of 2x(7x^2-2^4) ?
The derivative of 2x(7x^2-2^4) is 2((7x^2-2)^4+56x^2(7x^2-2)^3)
What is the first derivative of 2x(7x^2-2^4) ?
The first derivative of 2x(7x^2-2^4) is 2((7x^2-2)^4+56x^2(7x^2-2)^3)