What is the derivative of (-3x^2/(x^2-2x+1)) ?

The derivative of (-3x^2/(x^2-2x+1)) is (6x)/((x-1)^3)

What is the first derivative of (-3x^2/(x^2-2x+1)) ?

The first derivative of (-3x^2/(x^2-2x+1)) is (6x)/((x-1)^3)

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\frac{d}{d x} (\frac{- 3 x ^{2}}{x ^{2} - 2 x + 1})

\frac{6 x}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 3 x ^{2}}{x ^{2} - 2 x + 1})

Simplify

\frac{- 3 x ^{2}}{x ^{2} - 2 x + 1} : - \frac{3 x ^{2}}{x ^{2} - 2 x + 1}

= \frac{d}{d x} (- \frac{3 x ^{2}}{x ^{2} - 2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 3 \cdot \frac{\frac{d}{d x} ( x ^{2} ) ( x ^{2} - 2 x + 1 ) - \frac{d}{d x} ( x ^{2} - 2 x + 1 ) x ^{2}}{( x ^{2} - 2 x + 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{2} - 2 x + 1) = 2 x - 2

= - 3 \cdot \frac{2 x ( x ^{2} - 2 x + 1 ) - ( 2 x - 2 ) x ^{2}}{( x ^{2} - 2 x + 1 ) ^{2}}

Simplify

- 3 \cdot \frac{2 x ( x ^{2} - 2 x + 1 ) - ( 2 x - 2 ) x ^{2}}{( x ^{2} - 2 x + 1 ) ^{2}} : \frac{6 x}{( x - 1 ) ^{3}}

= \frac{6 x}{( x - 1 ) ^{3}}

n = 0 \sum \infty \frac{( 2 ^{n + 1} )}{5 ^{n}}

\int \frac{x}{5 x + 3} d x

\int \frac{1}{100} x + 10 d x

\frac{\partial}{\partial x} (ln (x^{7} + y^{3}))

What is the derivative of (-3x^2/(x^2-2x+1)) ?
The derivative of (-3x^2/(x^2-2x+1)) is (6x)/((x-1)^3)
What is the first derivative of (-3x^2/(x^2-2x+1)) ?
The first derivative of (-3x^2/(x^2-2x+1)) is (6x)/((x-1)^3)