What is (\partial)/(\partial y)(4xy+3x^2) ?

The answer to (\partial)/(\partial y)(4xy+3x^2) is 4x

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(\partial)/(\partial y)(4xy+3x^2)

\frac{\partial}{\partial y} (4 x y + 3 x^{2})

4 x

Solution steps

\frac{\partial}{\partial y} (4 x y + 3 x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x y) + \frac{\partial}{\partial y} (3 x^{2})

\frac{\partial}{\partial y} (4 x y) = 4 x

\frac{\partial}{\partial y} (3 x^{2}) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d}{d x} (- 9 e^{x - 9})

f (t) = 4 sin^{2} (t)

\int \frac{x}{x ^{2} + 3 x + 2} d x

\frac{d}{d x} (arctan (a x^{2}))

\int_{0}^{2} (x + 1)^{2} d x

What is (\partial)/(\partial y)(4xy+3x^2) ?
The answer to (\partial)/(\partial y)(4xy+3x^2) is 4x