What is the integral from 0 to sqrt(x of)t^2 ?

The integral from 0 to sqrt(x of)t^2 is (x^{3/2})/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to sqrt(x of)t^2

\int_{0}^{x} t^{2} d t

\frac{x ^{\frac{3}{2}}}{3}

Solution steps

\int_{0}^{x} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{x}

= [\frac{t ^{3}}{3}]_{0}^{x}

Compute the boundaries:

\frac{x ^{\frac{3}{2}}}{3}

= \frac{x ^{\frac{3}{2}}}{3}

h (x) = (- 2 x - 3)^{5} (3 x + 1)^{3}

f (x) = x^{4}, at x = 2

\int (\frac{9 + x}{x})^{2} d x

\int - csc (2 x) cot (2 x) d x

(2, 3), (- 4, - 3)

What is the integral from 0 to sqrt(x of)t^2 ?
The integral from 0 to sqrt(x of)t^2 is (x^{3/2})/3