What is the derivative of 3e^{3t} ?

The derivative of 3e^{3t} is 9e^{3t}

What is the first derivative of 3e^{3t} ?

The first derivative of 3e^{3t} is 9e^{3t}

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derivative of

3 e^{3 t}

9 e^{3 t}

Solution steps

\frac{d}{d t} (3 e^{3 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (e^{3 t})

Apply the chain rule:

e^{3 t} \frac{d}{d t} (3 t)

= e^{3 t} \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= 3 e^{3 t} \cdot 3

Simplify

= 9 e^{3 t}

f^{^{''}} (x) = e^{x}, f^{^{'}} (0) = 2, f (0) = 5

\int \frac{1}{1 - e ^{- x}} d x

\frac{\partial}{\partial y} (x^{4} + 3 y^{3})

y = 3 x^{2} + 6 x + 6

What is the derivative of 3e^{3t} ?
The derivative of 3e^{3t} is 9e^{3t}
What is the first derivative of 3e^{3t} ?
The first derivative of 3e^{3t} is 9e^{3t}