What is the derivative of (x^6/(x^3)) ?

The derivative of (x^6/(x^3)) is 3x^2

What is the first derivative of (x^6/(x^3)) ?

The first derivative of (x^6/(x^3)) is 3x^2

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\frac{d}{d x} (\frac{x ^{6}}{x ^{3}})

3 x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{6}}{x ^{3}})

Simplify

\frac{x ^{6}}{x ^{3}} : x^{3}

= \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x^{3 - 1}

Simplify

= 3 x^{2}

(3 x + 1)^{7}

f (x) = \frac{x ^{3} - 8}{x ^{2} - 4}

\frac{d}{d x} (x^{\frac{1}{10}})

\int u^{2} cos (u) d u

\frac{d}{d x} (\frac{x ^{2}}{2 + x})

What is the derivative of (x^6/(x^3)) ?
The derivative of (x^6/(x^3)) is 3x^2
What is the first derivative of (x^6/(x^3)) ?
The first derivative of (x^6/(x^3)) is 3x^2